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Mathematics · 2023

JEE Main · 31 January 2023, Shift 2 · Q71

Let y=y(x) be the solution of the differential equation (3 y^2-5 x^2) y d x+2 x(x^2-y^2) d y=0 such that y(1)=1. Then |(y(2))^3-12 y(2)| is equal to:

Let $\displaystyle y=y(x)$ be the solution of the differential equation $\displaystyle \left(3 y^2-5 x^2\right) y \mathrm{~d} x+2 x\left(x^2-y^2\right) \mathrm{d} y=0$ such that $\displaystyle y(1)=1$. Then $\displaystyle \left|(y(2))^3-12 y(2)\right|$ is equal to :
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