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Mathematics · 2023

JEE Main · 31 January 2023, Shift 1 · Q72

Let a differentiable function f satisfy f(x)+∫_3^x (f(t))/t d t=√(x+1), x ≥ 3. Then 12 f(8) is equal to:

Let a differentiable function $\displaystyle f$ satisfy $\displaystyle f(x)+\int_3^x \frac{f(t)}{t} d t=\sqrt{x+1}, x \geq 3$. Then $\displaystyle 12 f(8)$ is equal to :
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JEE Main 2023 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.