Mathematics · 2026
JEE Main · 28 January 2026, Shift 1 · Q19
Let y=y(x) be the solution of the differential equation x (d y)/(d x)- sin 2 y=x^3(2-x^3) cos^2 y, x ≠ 0. If y(2)=0, then tan (y(1)) is equal to
Let $\displaystyle y=y(x)$ be the solution of the differential equation $\displaystyle x \frac{d y}{d x}-\sin 2 y=x^3\left(2-x^3\right) \cos ^2 y, x \neq 0$.
If $\displaystyle y(2)=0$, then $\displaystyle \tan (y(1))$ is equal to
Official answer
From NTA’s final answer key for this paper.
(2)
$\displaystyle \frac{7}{4}$
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JEE Main 2026 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.