Let y=y(x) be the solution of the differential equation x (d y)/(d x)-y=x^2 cot x, x ∈(0, π). If y((π)/2)=(π)/2, then 6 y((π)/6)-8 y((π)/4) is equal…

Let $\displaystyle y=y(x)$ be the solution of the differential equation $\displaystyle x \frac{\mathrm{~d} y}{\mathrm{~d} x}-y=x^2 \cot x, x \in(0, \pi)$. If $\displaystyle y\left(\frac{\pi}{2}\right)=\frac{\pi}{2}$, then $\displaystyle 6 y\left(\frac{\pi}{6}\right)-8 y\left(\frac{\pi}{4}\right)$ is equal to :