Mathematics · 2022
JEE Main · 28 July 2022, Shift 2 · Q62
Let α, β be the roots of the equation x^2-√ 2 x+√ 6 =0 and 1/(α^2)+1, 1/(β^2)+1 be the roots of the equation x^2+a x+b=0. Then the roots of the…
Let $\displaystyle \alpha, \beta$ be the roots of the equation $\displaystyle x^2-\sqrt{2} x+\sqrt{6}=0$ and $\displaystyle \frac{1}{\alpha^2}+1, \frac{1}{\beta^2}+1$ be the roots of the equation $\displaystyle x^2+a x+b=0$. Then the roots of the equation $\displaystyle x^2-(a+b-2) x+(a+b+2)=0$ are:
Official answer
(2)
real and both negative
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JEE Main 2022 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.