Mathematics · 2023
JEE Main · 1 February 2023, Shift 2 · Q73
Let P (x_0, y_0) be the point on the hyperbola 3 x^2-4 y^2=36, which is nearest to the line 3 x+2 y=1. Then √ 2 (y_0-x_0) is equal to:
Let $\displaystyle \mathrm{P}\left(x_0, y_0\right)$ be the point on the hyperbola $\displaystyle 3 x^2-4 y^2=36$, which is nearest to the line $\displaystyle 3 x+2 y=1$. Then $\displaystyle \sqrt{2}\left(y_0-x_0\right)$ is equal to :
Official answer
From NTA’s final answer key for this paper.
(2)
$\displaystyle -9$
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JEE Main 2023 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.