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Mathematics · 2019

JEE Main · 11 January 2019, Shift 2 · Q73

Let x, y be positive real numbers and m, n positive integers. The maximum value of the expression (x^m y^n)/((1+x^2 m )(1+y^2 n )) is:

Let $\displaystyle x, y$ be positive real numbers and $\displaystyle \mathrm{m}, \mathrm{n}$ positive integers. The maximum value of the expression $\displaystyle \frac{x^{\mathrm{m}} y^{\mathrm{n}}}{\left(1+x^{2 \mathrm{~m}}\right)\left(1+y^{2 \mathrm{n}}\right)}$ is:
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JEE Main 2019 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.