Mathematics · 2020
JEE Main · 2 September 2020, Shift 2 · Q61
Let f:(-1, ∞) → R be defined by f(0)=1 and f(x)=1/x log_e (1+x), x ≠ 0. Then the function f:
Let $\displaystyle f:(-1, \infty) \rightarrow \mathbf{R}$ be defined by $\displaystyle f(0)=1$ and $\displaystyle f(x)=\frac{1}{x} \log _{\mathrm{e}}(1+x), x \neq 0$. Then the function $\displaystyle f$ :
Official answer
(4)
decreases in $\displaystyle (-1, \infty)$.
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JEE Main 2020 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.