Mathematics · 2021
JEE Main · 31 August 2021, Shift 2 · Q68
Let f be any continuous function on [0,2] and twice differentiable on (0,2). If f(0)=0, f(1)=1 and f(2)=2, then:
Let $\displaystyle f$ be any continuous function on $\displaystyle [0,2]$ and twice differentiable on $\displaystyle (0,2)$. If $\displaystyle f(0)=0$, $\displaystyle f(1)=1$ and $\displaystyle f(2)=2$, then :
Official answer
(3)
$\displaystyle f^{\prime \prime}(x)=0 \text { for some } x \in(0,2)$
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JEE Main 2021 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.