Mathematics · 2022
JEE Main · 29 June 2022, Shift 2 · Q20
Let n ≥ 5 be an integer. If 9^n-8 n-1=64 α and 6^n-5 n-1=25 β, then α-β is equal to
Let $\displaystyle n \geq 5$ be an integer. If $\displaystyle 9^n-8 n-1=64 \alpha$ and $\displaystyle 6^n-5 n-1=25 \beta$, then $\displaystyle \alpha-\beta$ is equal to
Official answer
(3)
$\displaystyle { }^n C_3(8-5)+{ }^n C_4\left(8^2-5^2\right)+\ldots+{ }^n C_n\left(8^{n-2}-5^{n-2}\right)$
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JEE Main 2022 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.