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Mathematics · 2019

JEE Main · 9 January 2019, Shift 1 · Q68

Let a_1, a_2, … …., a_30 be an A.P., S =Σ_i=1^30 a_i and T =Σ_i =1^15 a_(2 i -1). If a_5=27 and S -2 T =75, then a_10 is equal to:

Let $\displaystyle \mathrm{a}_1, \mathrm{a}_2, \ldots \ldots ., \mathrm{a}_{30}$ be an A.P., $\displaystyle \mathrm{S}=\sum_{i=1}^{30} \mathrm{a}_i$ and $$\mathrm{T}=\sum_{\mathrm{i}=1}^{15} \mathrm{a}_{(2 \mathrm{i}-1)} . \text { If } \mathrm{a}_5=27 \text { and } \mathrm{S}-2 \mathrm{~T}=75, $$ then $\displaystyle \mathrm{a}_{10}$ is equal to :
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JEE Main 2019 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.