Mathematics · 2025
JEE Main · 8 April 2025, Shift 2 · Q18
Let f(x) be a positive function and I_1=∫_-1/2^1 2 x f(2 x(1-2 x)) d x and I_2=∫_-1^2 f(x(1-x)) d x. Then the value of I_2/I_1 is equal to ____
Let $\displaystyle f(x)$ be a positive function and $\displaystyle I_1=\int_{-\frac{1}{2}}^1 2 x f(2 x(1-2 x)) d x$ and $\displaystyle I_2=\int_{-1}^2 f(x(1-x)) d x$. Then the value of $\displaystyle \frac{I_2}{I_1}$ is equal to $\displaystyle \_\_\_\_$
Official answer
From NTA’s final answer key for this paper.
(4)
$\displaystyle 4$
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JEE Main 2025 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.