Mathematics · 2018
JEE Main · 15 April 2018, Shift 2 · Q73
Let f(x) be a polynomial of degree 4 having extreme values at x=1 and x=2. If lim_x → 0((f(x))/x^2+1)=3 then f(-1) is equal to:
Let $\displaystyle f(x)$ be a polynomial of degree $\displaystyle 4$ having extreme values at $\displaystyle x=1$ and $\displaystyle x=2$.If $\displaystyle \lim _{x \rightarrow 0}\left(\frac{f(x)}{x^2}+1\right)=3$ then $\displaystyle f(-1)$ is equal to :
Official answer
(1)
$\displaystyle \frac{9}{2}$
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JEE Main 2018 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.