Mathematics · 2023
JEE Main · 25 January 2023, Shift 1 · Q67
Let x=2 be a local minima of the function f(x)=2 x^4-18 x^2+8 x+12, x ∈(-4,4). If M is local maximum value of the function f in (-4,4), then M =
Let $\displaystyle x=2$ be a local minima of the function $\displaystyle f(x)=2 x^4-18 x^2+8 x+12$, $\displaystyle x \in(-4,4)$. If M is local maximum value of the function $\displaystyle f$ in $\displaystyle (-4,4)$, then $\displaystyle \mathrm{M}=$
Official answer
From NTA’s final answer key for this paper.
(1)
$\displaystyle 12 \sqrt{6}-\frac{33}{2}$
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JEE Main 2023 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.