Mathematics · 2019
JEE Main · 11 January 2019, Shift 1 · Q67
Let a_1, a_2, …, a_10 be a G.P. If (a_3)/(a_1)=25, then (a_9)/(a_5) equals:
Let $\displaystyle \mathrm{a}_1, \mathrm{a}_2, \ldots, \mathrm{a}_{10}$ be a G.P. If $\displaystyle \frac{\mathrm{a}_3}{\mathrm{a}_1}=25$, then
$\displaystyle \frac{\mathrm{a}_9}{\mathrm{a}_5}$ equals :
Official answer
(4)
$\displaystyle 5^4$
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JEE Main 2019 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.