Mathematics · 2026
JEE Main · 5 April 2026, Shift 2 · Q6
Let A_1, A_2, A_3, … ….., A_39 be 39 arithmetic means between the numbers 59 and 159. Then the mean of A_25, A_28, A_31 and A_36 is equal to:
Let $\displaystyle \mathrm{A}_1, \mathrm{~A}_2, \mathrm{~A}_3, \ldots \ldots . ., \mathrm{A}_{39}$ be $\displaystyle 39$ arithmetic means between the numbers $\displaystyle 59$ and 159. Then the mean of $\displaystyle \mathrm{A}_{25}, \mathrm{~A}_{28}, \mathrm{~A}_{31}$ and $\displaystyle \mathrm{A}_{36}$ is equal to :
Official answer
From NTA’s final answer key for this paper.
(4)
$\displaystyle 134$
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JEE Main 2026 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.