If the sum of the first 10 terms of the series 1/(1+1^4 × 4)+2/(1+2^4 × 4)+3/(1+3^4 × 4)+4/(1+4^4 × 4)+… …. is m/n, gcd ( m, n )=1, then m + n is…

If the sum of the first $\displaystyle 10$ terms of the series $\displaystyle \frac{1}{1+1^4 \times 4}+\frac{2}{1+2^4 \times 4}+\frac{3}{1+3^4 \times 4}+\frac{4}{1+4^4 \times 4}+\ldots \ldots$. is $\displaystyle \frac{\mathrm{m}}{\mathrm{n}}, \operatorname{gcd}(\mathrm{m}, \mathrm{n})=1$, then $\displaystyle \mathrm{m}+\mathrm{n}$ is equal to :