Mathematics · 2021
JEE Main · 27 July 2021, Shift 2 · Q89
Let A={n ∈ N ∣ n^2 ≤ n+10,000}, B={3 k+1 ∣ k ∈ N} and C={2 k ∣ k ∈ N}, then the sum of all the elements of the set A ∩(B-C) is equal to \ \ \ \.
Let $\displaystyle A=\left\{n \in N \mid n^2 \leq n+10,000\right\}, B=\{3 k+1 \mid k \in N\}$ and $\displaystyle C=\{2 k \mid k \in N\}$, then the sum of all the elements of the set $\displaystyle A \cap(B-C)$ is equal to \_\_\_\_.
Official answer
832
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JEE Main 2021 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.