Let A={(x, y) ∈ R^2: y ≥ 0,2 x ≤ y ≤ √(4-(x-1)^2)} and B={(x, y) ∈ R × R: 0 ≤ y ≤ min {2 x, √(4-(x-1)^2)}}. Then the ratio of the area of A to the…

Let $\displaystyle A=\left\{(x, y) \in \mathbb{R}^2: y \geq 0,2 x \leq y \leq \sqrt{4-(x-1)^2}\right\}$ and $$B=\left\{(x, y) \in \mathbb{R} \times \mathbb{R}: 0 \leq y \leq \min \left\{2 x, \sqrt{4-(x-1)^2}\right\}\right\} . $$ Then the ratio of the area of $\displaystyle A$ to the area of $\displaystyle B$ is