Mathematics · 2016
JEE Main · 9 April 2016, Shift 1 · Q81
Let a and b respectively be the semi-transverse and semi-conjugate axes of a hyperbola whose eccentricity satisfies the equation 9 e^2-18 e+5=0. If…
Let $\displaystyle a$ and $\displaystyle b$ respectively be the semi-transverse and semi-conjugate axes of a hyperbola whose eccentricity satisfies the equation $\displaystyle 9 e^2-18 e+5=0$. If S$\displaystyle (5, 0)$ is a focus and $\displaystyle 5 x=9$ is the corresponding directrix of this hyperbola, then $\displaystyle a^2-b^2$ is equal to :
Official answer
(2)
$\displaystyle -7$
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JEE Main 2016 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.