Mathematics · 2016
JEE Main · 10 April 2016, Shift 1 · Q61
Let P ={θ: sin θ- cos θ=√ 2 cos θ} and Q ={θ: sin θ+ cos θ=√ 2 sin θ} be two sets. Then:
Let $\displaystyle \mathrm{P}=\{\theta: \sin \theta-\cos \theta=\sqrt{2} \cos \theta\}$ and $\displaystyle \mathrm{Q}=\{\theta: \sin \theta+\cos \theta=\sqrt{2} \sin \theta\}$ be two sets. Then :
Official answer
(4)
$\displaystyle \mathrm{P}=\mathrm{Q}$
More from Trigonometric Equations
- The number of solutions of the equation 2 θ- cos^2 θ+√2=0 in R is equal to \ \ \ \.2022
- If 2 cos θ+ sin θ=1(θ ≠ (π)/2), then 7 cos θ+6 sin θ is equal to:2014
- The number of solutions of the equation (4-√3) sin x-2 √3 cos^2 x=-4/(1+√3), x ∈[-2 π, (5 π)/2] is2025
- If the equation cos^4 θ+ sin^4 θ+λ=0 has real solutions for θ, then λ lies in the interval:2020
- The number of elements in the set S={θ ∈[0,2 π]: 3 cos^4 θ-5 cos^2 θ-2 sin^6 θ+2=0} is2023
- The number of solutions, of the equation e^sin x-2 e^- sin x=2, is:2024
- The number of solutions of | cos x|= sin x, such that -4 π ≤ x ≤ 4 π is:2022
- If 0 ≤ x<(π)/2, then the number of values of x for which sin x- sin 2 x+ sin 3 x=0, is:2019
JEE Main 2016 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.