Let g (x)= cos x^2, f(x)=√ x, and α, β(α<β) be the roots of the quadratic equation 18 x^2-9 π x+π^2=0. Then the area (in sq. units) bounded by the…

Let $\displaystyle \mathrm{g}(x)=\cos x^2, \quad f(x)=\sqrt{x}$, and $\displaystyle \alpha, \beta(\alpha<\beta)$ be the roots of the quadratic equation $\displaystyle 18 x^2-9 \pi x+\pi^2=0$. Then the area (in sq. units) bounded by the curve $\displaystyle y=(g \circ f)(x)$ and the lines $\displaystyle x=\alpha, x=\beta$ and $\displaystyle y=0$, is :