It the area enclosed by the parabolas P_1: 2 y =5 x^2 and P_2: x^2- y +6=0 is equal to the area enclosed by P_1 and y =α x, α>0, then α^3 is equal to…

It the area enclosed by the parabolas $\displaystyle \mathrm{P}_1: 2 \mathrm{y}=5 x^2$ and $\displaystyle \mathrm{P}_2: x^2-\mathrm{y}+6=0$ is equal to the area enclosed by $\displaystyle \mathrm{P}_1$ and $\displaystyle \mathrm{y}=\alpha x, \alpha>0$, then $\displaystyle \alpha^3$ is equal to $\displaystyle \_\_\_\_$.