Mathematics · 2021
JEE Main · 3 August 2021, Shift 1 · Q70
∫_1^2[x^2-1]+[x^2+1] d x is equal to ([t] denotes the greatest integer ≤ t)
$\displaystyle \int_1^2\left[x^2-1\right]+\left[x^2+1\right] d x$ is equal to $\displaystyle ([t]$ denotes the greatest integer $\displaystyle \leq t)$
Official answer
(4)
$\displaystyle 10-2 \sqrt{2}-2 \sqrt{3}$
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JEE Main 2021 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.