Mathematics · 2021
JEE Main · 27 August 2021, Shift 1 · Q77
∫_6^16 (log_e x^2)/(log_e x^2+ log_e (x^2-44 x+484)) d x is equal to:
$\displaystyle \int_6^{16} \frac{\log _{\mathrm{e}} x^2}{\log _{\mathrm{e}} x^2+\log _{\mathrm{e}}\left(x^2-44 x+484\right)} \mathrm{d} x$ is equal to :
Official answer
(4)
$\displaystyle 5$
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JEE Main 2021 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.