Mathematics · 2023
JEE Main · 6 April 2023, Shift 2 · Q9
lim_n → ∞{(2^(1/2)-2^(1/3))(2^(1/2)-2^(1/5)) … …(2^(1/2)-2^(1/(2 n+1)))} is equal to
$\displaystyle \lim _{n \rightarrow \infty}\left\{\left(2^{\frac{1}{2}}-2^{\frac{1}{3}}\right)\left(2^{\frac{1}{2}}-2^{\frac{1}{5}}\right) \ldots \ldots\left(2^{\frac{1}{2}}-2^{\frac{1}{2 n+1}}\right)\right\}$ is equal to
Official answer
From NTA’s final answer key for this paper.
(2)
$\displaystyle 0$
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JEE Main 2023 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.