Mathematics · 2021
JEE Main · 26 August 2021, Shift 2 · Q65
lim_x → 2(Σ_n =1^9 x/(n ( n +1) x^2+2(2 n +1) x+4)) is equal to:
$\displaystyle \lim _{x \rightarrow 2}\left(\sum_{\mathrm{n}=1}^9 \frac{x}{\mathrm{n}(\mathrm{n}+1) x^2+2(2 \mathrm{n}+1) x+4}\right)$ is equal to :
Official answer
(3)
$\displaystyle \frac{9}{44}$
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JEE Main 2021 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.