Mathematics · 2021
JEE Main · 25 February 2021, Shift 2 · Q74
lim_n → ∞[1/n+n/((n+1)^2)+n/((n+2)^2)+… … …+n/((2 n-1)^2)] is equal to:
$\displaystyle \lim _{n \rightarrow \infty}\left[\frac{1}{n}+\frac{n}{(n+1)^2}+\frac{n}{(n+2)^2}+\ldots \ldots \ldots+\frac{n}{(2 n-1)^2}\right]$ is equal to :
Official answer
(2)
$\displaystyle \frac{1}{2}$
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JEE Main 2021 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.