Mathematics · 2020
JEE Main · 9 January 2020, Shift 2 · Q62
If ∫ (d θ)/(cos^2 θ( tan 2 θ+ sec 2 θ))= λ tan θ+2 log_e |f(θ)|+C where C is a constant of integration, then the ordered pair ( λ, f(θ) ) is equal to:
If $\displaystyle \int \frac{\mathrm{d} \theta}{\cos ^2 \theta(\tan 2 \theta+\sec 2 \theta)}=$
$\displaystyle \lambda \tan \theta+2 \log _{\mathrm{e}}|f(\theta)|+C$ where $\displaystyle C$ is a constant of integration, then the ordered pair ( $\displaystyle \lambda, f(\theta)$ ) is equal to :
Official answer
(1)
$\displaystyle (-1,1+\tan \theta)$
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JEE Main 2020 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.