Mathematics · 2019
JEE Main · 11 January 2019, Shift 2 · Q74
If ∫ (x+1)/(√(2 x-1)) d x=f(x) √(2 x-1)+ C, where C is a constant of integration, then f(x) is equal to:
If $\displaystyle \int \frac{x+1}{\sqrt{2 x-1}} \mathrm{~d} x=f(x) \sqrt{2 x-1}+\mathrm{C}$, where C is a constant of integration, then $\displaystyle f(x)$ is equal to :
Official answer
(4)
$\displaystyle \frac{1}{3}(x+4)$
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JEE Main 2019 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.