If Σ_k=1^10 k/(k^4+k^2+1)=m/n, where m and n are co-prime, then m+n is equal to \ \ \ \

If $\displaystyle \sum_{k=1}^{10} \frac{k}{k^4+k^2+1}=\frac{m}{n}$, where $\displaystyle m$ and $\displaystyle n$ are co-prime, then $\displaystyle m+n$ is equal to \_\_\_\_