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Mathematics · 2026

JEE Main · 28 January 2026, Shift 1 · Q12

If (tan ( A - B ))/(tan A)+(sin^2 C)/(sin^2 A)=1, A, B, C ∈(0, (π)/2), then

If $\displaystyle \frac{\tan (\mathrm{A}-\mathrm{B})}{\tan \mathrm{A}}+\frac{\sin ^2 \mathrm{C}}{\sin ^2 \mathrm{~A}}=1, \mathrm{~A}, \mathrm{~B}, \mathrm{C} \in\left(0, \frac{\pi}{2}\right)$, then
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JEE Main 2026 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.