Mathematics · 2021
JEE Main · 4 August 2021, Shift 1 · Q86
If ∫(√(tan x)+√(cot x)) d x=a tan^-1((tan x-1)/(√(b tan x)))+ C, then the value of a^4+b^5 is \ \ \ \. (Here, C is a constant of integration).
If $\displaystyle \int(\sqrt{\tan x}+\sqrt{\cot x}) d x=a \tan ^{-1}\left(\frac{\tan x-1}{\sqrt{b \tan x}}\right)+\mathrm{C}$, then the value of $\displaystyle a^4+b^5$ is \_\_\_\_.
(Here, C is a constant of integration).
Official answer
36
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JEE Main 2021 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.