Mathematics · 2022
JEE Main · 25 June 2022, Shift 1 · Q8
If 1/(2 · 3^10)+1/(2^2 · 3^9)+…+1/(2^10 · 3)=K/(2^10 · 3^10), then the remainder when K is divided by 6 is:
If $\displaystyle \frac{1}{2 \cdot 3^{10}}+\frac{1}{2^2 \cdot 3^9}+\ldots+\frac{1}{2^{10} \cdot 3}=\frac{\mathrm{K}}{2^{10} \cdot 3^{10}}$, then the remainder when K is divided by $\displaystyle 6$ is :
Official answer
(4)
$\displaystyle 5$
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JEE Main 2022 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.