SolveIt is under development
SolveItJEE Main
Question 205 / 299 · latest first
Mathematics · 2021

JEE Main · 31 August 2021, Shift 1 · Q63

If a_r = cos (2 r π)/9+i sin (2 r π)/9, r =1,2,3, …, i=√ -1, then the determinant |a_1, a_2, a_3; a_4, a_5, a_6; a_7, a_8, a_9| is equal to:

If $\displaystyle \mathrm{a}_{\mathrm{r}}=\cos \frac{2 \mathrm{r} \pi}{9}+i \sin \frac{2 \mathrm{r} \pi}{9}, \mathrm{r}=1,2,3, \ldots, i=\sqrt{-1}$, then the determinant $\displaystyle \left|\begin{array}{lll}a_1 & a_2 & a_3 \\ a_4 & a_5 & a_6 \\ a_7 & a_8 & a_9\end{array}\right|$ is equal to :
ShareWhatsAppTelegram

More from Matrices and Determinants

JEE Main 2021 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.