Mathematics · 2021
JEE Main · 31 August 2021, Shift 1 · Q64
If the following system of linear equations 2 x+y+z=5; x-y+z=3; x+y+ a z= b has no solution, then:
If the following system of linear equations
$$\begin{aligned}
& 2 x+y+z=5 \\
& x-y+z=3 \\
& x+y+\mathrm{a} z=\mathrm{b}
\end{aligned}
$$
has no solution, then :
Official answer
(1)
$\displaystyle a=\frac{1}{3}, b \neq \frac{7}{3}$
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JEE Main 2021 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.