Mathematics · 2020
JEE Main · 5 September 2020, Shift 1 · Q57
If 2^10+2^9 · 3^1+2^8 · 3^2+….+2 · 3^9+3^10= S -2^11, then S is equal to:
If
$$2^{10}+2^9 \cdot 3^1+2^8 \cdot 3^2+\ldots .+2 \cdot 3^9+3^{10}=\mathrm{S}-2^{11},
$$
then S is equal to :
Official answer
(1)
$\displaystyle 3^{11}$
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JEE Main 2020 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.