Mathematics · 2018
JEE Main · 15 April 2018, Shift 1 · Q74
If f((x-4)/(x+2))=2 x+1,(x ∈ R -{1,-2}), then ∫ f(x) d x is equal to: (where C is a constant of integration)
If $\displaystyle f\left(\frac{x-4}{x+2}\right)=2 x+1,(x \in \mathbf{R}-\{1,-2\})$, then $\displaystyle \int f(x) \mathrm{d} x$ is equal to : (where C is a constant of integration)
Official answer
(2)
$\displaystyle -12 \log _{\mathrm{e}}|1-x|-3 x+\mathrm{C}$
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JEE Main 2018 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.