Mathematics · 2025
JEE Main · 29 January 2025, Shift 2 · Q13
If sin x+ sin^2 x=1, x ∈(0, (π)/2), then ( cos^12 x+ tan^12 x)+3( cos^10 x+ tan^10 x+ cos^8 x+ tan^8 x)+( cos^6 x+ tan^6 x) is equal to:
If $\displaystyle \sin x+\sin ^2 x=1, x \in\left(0, \frac{\pi}{2}\right)$, then $\displaystyle \left(\cos ^{12} x+\tan ^{12} x\right)+3\left(\cos ^{10} x+\tan ^{10} x+\cos ^8 x+\tan ^8 x\right)+\left(\cos ^6 x+\tan ^6 x\right)$ is equal to :
Official answer
From NTA’s final answer key for this paper.
(2)
$\displaystyle 2$
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JEE Main 2025 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.