Mathematics · 2024
JEE Main · 27 January 2024, Shift 2 · Q8
If lim_x → 0 (3+α sin x+β cos x+ log_e (1-x))/(3 tan^2 x)=1/3, then 2 α-β is equal to:
If $\displaystyle \lim _{x \rightarrow 0} \frac{3+\alpha \sin x+\beta \cos x+\log _{\mathrm{e}}(1-x)}{3 \tan ^2 x}=\frac{1}{3}$, then $\displaystyle 2 \alpha-\beta$ is equal to :
Official answer
From NTA’s final answer key for this paper.
(1)
$\displaystyle 5$
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JEE Main 2024 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.