Mathematics · 2016
JEE Main · 9 April 2016, Shift 1 · Q75
If 2 ∫_0^1 tan^-1 x d x=∫_0^1 cot^-1(1-x+x^2) d x, then ∫_0^1 tan^-1(1-x+x^2) d x is equal to:
If $\displaystyle 2 \int_0^1 \tan ^{-1} x d x=\int_0^1 \cot ^{-1}\left(1-x+x^2\right) d x$, then $\displaystyle \int_0^1 \tan ^{-1}\left(1-x+x^2\right) d x$ is equal to :
Official answer
(3)
$\displaystyle \log 2$
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JEE Main 2016 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.