If ∫_-(π)/2^((π)/2) (96 x^2 cos^2 x)/((1+e^x)) d x=π(α π^2+β), α, β ∈ Z, then (α+β)^2 equals

If $\displaystyle \int_{-\frac{\pi}{2}}^{\frac{\pi}{2}} \frac{96 x^2 \cos ^2 x}{\left(1+e^x\right)} \mathrm{d} x=\pi\left(\alpha \pi^2+\beta\right), \alpha, \beta \in \mathbb{Z}$, then $\displaystyle (\alpha+\beta)^2$ equals