If ∫_0^2(√(2 x)-√(2 x-x^2)) d x=∫_0^1(1-√(1-y^2)-y^2/2) d y+∫_1^2(2-y^2/2) d y+I then I equals

If $\displaystyle \int_0^2\left(\sqrt{2 x}-\sqrt{2 x-x^2}\right) d x=\int_0^1\left(1-\sqrt{1-y^2}-\frac{y^2}{2}\right) d y+\int_1^2\left(2-\frac{y^2}{2}\right) d y+I$ then $\displaystyle I$ equals