Mathematics · 2022
JEE Main · 30 July 2022, Shift 2 · Q70
If y(x)= tan x-∫_0^2 x(x^2-x t+1) sin t d t, then at x=(π)/3, the value of 2 y^′ ′ ′-y^′ ′ is equal to
If $\displaystyle y(x)=\tan x-\int_0^{2 x}\left(x^2-x t+1\right) \sin t d t$, then at $\displaystyle x=\frac{\pi}{3}$, the value of $\displaystyle 2 y^{\prime \prime \prime}-y^{\prime \prime}$ is equal to
Official answer
(1)
$\displaystyle 158$
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JEE Main 2022 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.