Mathematics · 2022
JEE Main · 29 July 2022, Shift 1 · Q28
If 1/(2 × 3 × 4)+1/(3 × 4 × 5)+1/(4 × 5 × 6)+…+1/(100 × 101 × 102)=k/101, then 34 k is equal to \ \ \ \.
If $\displaystyle \frac{1}{2 \times 3 \times 4}+\frac{1}{3 \times 4 \times 5}+\frac{1}{4 \times 5 \times 6}+\ldots+\frac{1}{100 \times 101 \times 102}=\frac{\mathrm{k}}{101}$, then $\displaystyle 34$ k is equal to \_\_\_\_.
Official answer
286
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JEE Main 2022 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.