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Mathematics · 2025

JEE Main · 22 January 2025, Shift 2 · Q4

If the system of linear equations: x+y+2 z=6; 2 x+3 y+ a z= a +1; -x-3 y+ b z=2 b where a, b ∈ R, has infinitely many solutions, then 7 a +3 b is…

If the system of linear equations : $$\begin{aligned} & x+y+2 z=6 \\ & 2 x+3 y+\mathrm{a} z=\mathrm{a}+1 \\ & -x-3 y+\mathrm{b} z=2 \mathrm{~b} \end{aligned} $$ where $\displaystyle \mathrm{a}, \mathrm{b} \in \mathbf{R}$, has infinitely many solutions, then $\displaystyle 7 \mathrm{a}+3 \mathrm{~b}$ is equal to :
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JEE Main 2025 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.