Mathematics · 2025
JEE Main · 24 January 2025, Shift 2 · Q5
If the system of equations x+2 y-3 z=2; 2 x+λ y+5 z=5; 14 x+3 y+μ z=33 has infinitely many solutions, then λ+μ is equal to:
If the system of equations
$$\begin{aligned}
& x+2 y-3 z=2 \\
& 2 x+\lambda y+5 z=5 \\
& 14 x+3 y+\mu z=33
\end{aligned}
$$
has infinitely many solutions, then $\displaystyle \lambda+\mu$ is equal to :
Official answer
From NTA’s final answer key for this paper.
(3)
$\displaystyle 12$
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JEE Main 2025 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.