Mathematics · 2024
JEE Main · 9 April 2024, Shift 1 · Q5
If the sum of the series 1/(1 ·(1+d))+1/((1+d)(1+2 d))+…+1/((1+9 d)(1+10 d)) is equal to 5, then 50 d is equal to:
If the sum of the series $\displaystyle \frac{1}{1 \cdot(1+d)}+\frac{1}{(1+d)(1+2 d)}+\ldots+\frac{1}{(1+9 d)(1+10 d)}$ is equal to $\displaystyle 5$ , then $\displaystyle 50$ d is equal to :
Official answer
From NTA’s final answer key for this paper.
(1)
$\displaystyle 5$
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JEE Main 2024 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.