Mathematics · 2020
JEE Main · 5 September 2020, Shift 2 · Q57
If the sum of the first 20 terms of the series log_(7^1 / 2) x+ log_(7^1 / 3) x+ log_(7^1 / 4) x+… is 460, then x is equal to:
If the sum of the first $\displaystyle 20$ terms of the series $\displaystyle \log _{\left(7^{1 / 2}\right)} x+\log _{\left(7^{1 / 3}\right)} x+\log _{\left(7^{1 / 4}\right)} x+\ldots \quad$ is $\displaystyle 460$ , then $\displaystyle x$ is equal to :
Official answer
(3)
$\displaystyle 7^2$
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JEE Main 2020 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.