Mathematics · 2019
JEE Main · 12 January 2019, Shift 2 · Q69
If the sum of the first 15 terms of the series (3/4)^3+(1 1/2)^3+(2 1/4)^3+3^3+(3 3/4)^3+….. is equal to 225 k, then k is equal to:
If the sum of the first $\displaystyle 15$ terms of the series
$$\left(\frac{3}{4}\right)^3+\left(1 \frac{1}{2}\right)^3+\left(2 \frac{1}{4}\right)^3+3^3+\left(3 \frac{3}{4}\right)^3+\ldots . .
$$
is equal to $\displaystyle 225$ k, then k is equal to :
Official answer
(2)
$\displaystyle 27$
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JEE Main 2019 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.